ch28-p070 - 70. (a) We use Eq. 28-10: vd = E/B = (10...

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70. (a) We use Eq. 28-10: v d = E / B = (10 × 10 –6 V/1.0 × 10 –2 m)/(1.5 T) = 6.7 × 10 –4 m/s. (b) We rewrite Eq. 28-12 in terms of the electric field: n Bi Ve Bi Ed e Bi EAe == = AA b g which we use Ad = A . In this experiment, A = (0.010 m)(10 × 10 –6 m) = 1.0 × 10 –7 m 2 . By Eq. 28-10, v d equals the ratio of the fields (as noted in part (a)), so we are led to () ( ) ( ) 29 3 47 2 1 9 3.0A 2.8 10 m . 6.7 10 m s 1.0 10 m 1.6 10 C d Bi i n EAe vAe −− === = × ×× × (c) Since a drawing of an inherently 3-D situation can be misleading, we describe it in terms of horizontal
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This note was uploaded on 06/03/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.

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