EnevCd=ρ. Now, regarding the Hall effect, we use Eq. 28-10 to write E = vdB. Dividing one equation by the other, we get E/Ec= B/ne. (b) Using the value of copper’s resistivity given in Chapter 26, we obtain ()()()32831980.65 T2.84 10 .8.47 10m1.60 10C 1.69 10mcEBe−−−===××××Ω⋅
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This note was uploaded on 06/03/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.