ch28-p082 - 82. (a) We are given B = Bx = (6 105T)i , so...

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82. (a) We are given 5 ˆˆ i( 61 0T ) i x BB == × G , so that G G vB vB yx ×= ± k where v y = 4 × 10 4 m/s. We note that the magnetic force on the electron is −− ev B b g e j ± k and therefore points in the + ± k direction, at the instant the electron enters the field-filled region. In these terms, Eq. 28-16 becomes r mv eB ey x 0 0038 .m . (b) One revolution takes T = 2 π r / v y = 0.60 µ s, and during that time the “drift” of the electron in the x direction (which is the pitch of the helix) is x = v x T = 0.019 m where
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