current: out of the page. With wire 3 infinitely far away, the force per unit length is given (in magnitude) as 6.27×10−7 N/m. We set this equal to 120 1 2/2Fiidµπ=. When wire 3 is at x= 0.04 m the curve passes through the zero point previously mentioned, so the force between 2 and 3 must equal F12 there. This allows us to solve for the distance between wire 1 and wire 2: d= (0.04 m)(0.750 A)/(0.250 A) = 0.12 m. Then we solve 6.27×10−7 N/m= µo i1i2/2πdand obtain i2= 0.50 A. (b) The direction of i2is out of the page. 40. (a) The fact that the curve in Fig. 29-65(b) passes through zero implies that the
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This note was uploaded on 06/03/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.