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current:
out of the page
.
With wire 3 infinitely far away, the force per unit length is given
(in magnitude) as 6.27
×
10
−
7
N/m.
We set this equal to
12
0 1 2
/2
Fi
i
d
µ
π
=
. When wire 3
is at
x
= 0.04 m the curve passes through the zero point previously mentioned, so the
force between 2 and 3 must equal
F
12
there.
This allows us to solve for the distance
between wire 1 and wire 2:
d
= (0.04 m)(0.750 A)/(0.250 A) = 0.12 m.
Then we solve 6.27
×
10
−
7
N/m=
µ
o
i
1
i
2
/2
π
d
and obtain
i
2
= 0.50 A.
(b) The direction of
i
2
is out of the page.
40. (a) The fact that the curve in Fig. 2965(b) passes through zero implies that the
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This note was uploaded on 06/03/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.
 Spring '08
 Any
 Physics, Current, Force

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