(x, y, z) = (0, 5.0 m, 0) 62211033ˆ(1.26 10T m/A)(6.0 10 mA) jˆ(0, 5.0 m, 0)(9.6 10T) j .22m)Byµ−−−×⋅×⋅≈==×ππ(5.0GG61. By imagining that each of the segments bgand cf(which are shown in the figure as having no current) actually has a pair of currents, where both currents are of the same magnitude (i) but opposite direction (so that the pair effectively cancels in the final sum),
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