Ch29-p068 - 68 We note that the distance from each wire to P is r = d the current is i = 100 A 2 = 0.071 m In both parts(a With the currents

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68. We note that the distance from each wire to P is rd == 2 0 071 . m. In both parts, the current is i = 100 A. (a) With the currents parallel, application of the right-hand rule (to determine each of their contributions to the field at P ) reveals that the vertical components cancel and the horizontal components add, yielding the result: 4 0 2 cos45.0 4.00 10 T 2 i B r µ ⎛⎞ = × ⎜⎟ ⎝⎠ π and directed in the – x direction. In unit-vector notation, we have
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This note was uploaded on 06/03/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.

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