ch29-p076 - 76 We take the current(i = 50 A to flow in the...

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76. We take the current ( i = 50 A) to flow in the + x direction, and the electron to be at a point P which is r = 0.050 m above the wire (where “up” is the + y direction). Thus, the field produced by the current points in the + z direction at P . Then, combining Eq. 29-4 with Eq. 28-2, we obtain G G Fe i r v e =− × µ 0 2 π b g e j ± . k (a) The electron is moving down: G vv ± j (where v = 1.0 × 10 7 m/s is the speed) so ( )
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This note was uploaded on 06/03/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.

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