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78. Eq. 2917 applies for each wire, with
rRd
=+
2
2
2
/
b
g
(by the Pythagorean
theorem). The vertical components of the fields cancel, and the two (identical) horizontal
components add to yield the final result
()
6
00
2
2
/2
21
.
2
5
1
0
T
2
2/
2
ii
d
d
B
rr
Rd
µµ
π
−
⎛⎞
==
=
×
⎜⎟
⎝⎠
+
,
where (
d
/2)/
r
is a trigonometric factor to select the horizontal component. It is clear that
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 Spring '08
 Any
 Physics

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