ch29-p079 - 79 The current per unit x-length may be viewed...

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the nearest one should contribute an upward component to the field at P . The current elements are all equivalent, as is reflected in the horizontal-translational symmetry built into this problem; therefore, all vertical components should cancel in pairs. The field at P must be purely horizontal, as drawn. (b) The path used in evaluating G G Bd s z is rectangular, of horizontal length x (the horizontal sides passing through points P and P' respectively) and vertical size δ y > y . The vertical sides have no contribution to the integral since G B is purely horizontal (so the scalar dot product produces zero for those sides), and the horizontal sides contribute two equal terms, as shown next. Ampere’s law yields 00 1 2. 2 Bx x B µ λµλ ∆= ∆ ⇒ = 79. The “current per unit x -length” may be viewed as current density multiplied by the thickness y of the sheet; thus, λ = J y . Ampere’s law may be (and often is) expressed in terms of the current density vector as follows
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This note was uploaded on 06/03/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.

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