83. We refer to the center of the circle (where we are evaluating GB) as C. Recalling the straight sectionsdiscussion in Sample Problem 29-1, we see that the current in the straight segments which are collinear with Cdo not contribute to the field there. Eq. 29-9 (with φ= π/2 rad) and the right-hand rule indicates that the currents in the two arcs contribute µµ000iRiRπ24π4πbg−=to the field at C. Thus, the non-zero contributions come from those straight-segments which are not collinear with C. There are two of these “semi-infinite” segments, one a vertical distance
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