222025/2227/2225/227/23152()()5().(2))NiRdBxdxRxxssxssxsµ⎡=−+⎢++⎣⎤−−+⎥+−++⎦At x = s/2, 2025/2227/2/2222220022 7/2/2630/4/4)(/4)6(/ 4) 30/ 43.2(/4)(sRsdxRsRsNRR sss RRRs⎡⎤+⎢⎥⎣⎦+−==Clearly, this is zero if s = R. 86. (a) The magnitude of the magnetic field on the axis of a circular loop, a distance zfrom the loop center, is given by Eq. 29-26: BRRz=+0232),/where Ris the radius of the loop, Nis the number of turns, and iis the current. Both of the loops in the problem have the same radius, the same number of turns, and carry the same current. The currents are in the same sense, and the fields they produce are in the same direction in the region between them. We place the origin at the center of the left-hand loop and let xbe the coordinate of a point on the axis between the loops. To calculate the field of the left-hand loop, we set z = xin the equation above. The chosen point on the axis is a distance
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This note was uploaded on 06/03/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.