vWmmiwRLf=FHGIKJ=+FHGIKJLNMOQP=×⋅×+×LNMMOQPP=×−−22212 410450 101 124 02101023 10120273233extTm/AAcm/6.7cmmkgm/s.///lnln...µπππchchbgbgch90. (a) Consider a segment of the projectile between yand y + dy. We use Eq. 29-12 to find the magnetic force on the segment, and Eq. 29-7 for the magnetic field of each semi-infinite wire (the top rail referred to as wire 1 and the bottom as wire 2). The current in rail 1 is in the +±i direction, and the current in rail 2 is in the −±i direction. The field (in the region between the wires) set up by wire 1 is into the paper (the −±k direction) and that set up by wire 2 is also into the paper. The force element (a function of y) acting on the segment of the projectile (in which the current flows in the
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This note was uploaded on 06/03/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.