ch30-p012 - 6 T/s 5.010 6 T/s ) = 4.010 8 V. The minus sign...

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12. (a) Since the flux arises from a dot product of vectors, the result of one sign for B 1 and B 2 and of the opposite sign for B 3 (we choose the minus sign for the flux from B 1 and B 2 , and therefore a plus sign for the flux from B 3 ). The induced emf is ε = Σ d Φ B dt = A dB 1 dt + dB 2 dt dB 3 dt =(0.10 m)(0.20 m) ( 2.0 × 10 6 T/s + 1.0 × 10
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Unformatted text preview: 6 T/s 5.010 6 T/s ) = 4.010 8 V. The minus sign meaning that the effect is dominated by the changes in B 3 . Its magnitude (using Ohms law) is | | / R = 8.0 A. (b) Consideration of Lenzs law leads to the conclusion that the induced current is therefore counterclockwise....
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This note was uploaded on 06/03/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.

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