ch30-p027 - 27. (a) We refer to the (very large) wire...

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which yields Φ B / L = 1.3 × 10 –5 T·m or 1.3 × 10 –5 Wb/m. (b) The flux (per meter) existing within the regions of space occupied by one or the other wires was computed above to be 0.23 × 10 –5 T·m. Thus, 5 5 0.23 10 T m 0.17 17% . 1.3 10 T m ×⋅ == (c) What was described in part (a) as a symmetry plane at x = A /2 is now (in the case of parallel currents) a plane of vanishing field (the fields subtract from each other in the region between them, as the right-hand rule shows). The flux in the 02 < < x A / region is now of opposite sign of the flux in the AA < < x region which causes the total flux (or, in this case, flux per meter) to be zero. 27. (a) We refer to the (very large) wire length as L and seek to compute the flux per meter: Φ B / L . Using the right-hand rule discussed in Chapter 29, we see that the net field in the region between the axes of anti-parallel currents is the addition of the magnitudes of their individual fields, as given by Eq. 29-17 and Eq. 29-20. There is an evident reflection symmetry in the problem, where the plane of symmetry is midway between the
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