which yields ΦB/L= 1.3 ×10–5T·m or 1.3 ×10–5Wb/m. (b) The flux (per meter) existing within the regions of space occupied by one or the other wires was computed above to be 0.23 ×10–5T·m. Thus, 550.23 10 T m0.1717% .1.3 10 T m−−×⋅==(c) What was described in part (a) as a symmetry plane at x=A/2is now (in the case of parallel currents) a plane of vanishing field (the fields subtract from each other in the region between them, as the right-hand rule shows). The flux in the02<<xA/region is now of opposite sign of the flux in the AA<<xregion which causes the total flux (or, in this case, flux per meter) to be zero. 27. (a) We refer to the (very large) wire length as Land seek to compute the flux per meter: ΦB/L. Using the right-hand rule discussed in Chapter 29, we see that the net field in the region between the axes of anti-parallel currents is the addition of the magnitudes of their individual fields, as given by Eq. 29-17 and Eq. 29-20. There is an evident reflection symmetry in the problem, where the plane of symmetry is midway between the
This is the end of the preview. Sign up
access the rest of the document.