ch30-p029 - 29. Thermal energy is generated at the rate P =...

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
ε == = d dt A dB dt Ld B dt B Φ loop 2 4 π where the rate of change of the field is dB / dt = 0.0100 T/s. Consequently, we obtain () 2 22 2 22 3 3 2 3 2 28 6 ( / 4 ) ( / ) (1.00 10 m) (0.500 m) 0.0100 T/s /( / 4) 64 64 (1.69 10 m) 3.68 10 W . B d t d L d B P RL d d t επ ρπ π ρ × ⎛⎞ = = ⎜⎟ ×Ω ⎝⎠ 29. Thermal energy is generated at the rate P = 2 / R (see Eq. 27-23). Using Eq. 27-16, the resistance is given by R = L / A , where the resistivity is 1.69 × 10 –8 ·m (by Table 27-1) and A = π d 2 /4 is the cross-sectional area of the wire (
Background image of page 1
This is the end of the preview. Sign up to access the rest of the document.
Ask a homework question - tutors are online