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54. From the graph we get
Φ
/
i
= 2
×
10
−
4
in SI units.
Therefore, with
N
= 25, we find the
selfinductance is
L = N
Φ
/
i
= 5
×
10
−
3
H.
From the derivative of Eq. 3041 (or a
combination of that equation and Eq. 3039) we find (using the symbol V to stand for the
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This note was uploaded on 06/03/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.
 Spring '08
 Any
 Physics, Inductance

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