ch30-p056

# ch30-p056 - 56. (a) The inductor prevents a fast build-up...

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(g) i 1 = 0, and (h) i 2 = 0. 56. (a) The inductor prevents a fast build-up of the current through it, so immediately after the switch is closed, the current in the inductor is zero. It follows that 1 12 100V 3.33A. 10.0 +20.0 i RR ε == = +Ω (b) 21 3.33A. ii (c) After a suitably long time, the current reaches steady state. Then, the emf across the inductor is zero, and we may imagine it replaced by a wire. The current in R 3 is i 1 i 2 . Kirchhoff’s loop rule gives () 11 2 2 1 2 3 0 0. iR iR iR i i R −= −− = We solve these simultaneously for i 1 and i 2 , and find ( )( ) 23 1 13 20.0 30.0 10.0 20.0 10.0 30.0 20.0 30.0 4.55A, i + ++ + + = (d) and ( )( ) 3 2 30.0 10.0 20.0 10.0 30.0 20.0 30.0 2.73A. R i + + = (e) The left-hand branch is now broken. We take the current (immediately) as zero in that
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## This note was uploaded on 06/03/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.

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