ch30-p061 - 61. From Eq. 30-49 and Eq. 30-41, the rate at...

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Pi R R eR R e tt LL thermal == = −− 2 2 2 2 2 2 11 εε ττ chch . We equate this to dU B / dt , and solve for the time: () 22 2 1 1 ln 2 37.0ms ln 2 25.6ms. L t L ee e t RR τ −= = = = 61. From Eq. 30-49 and Eq. 30-41, the rate at which the energy is being stored in the inductor is 2 2 /2 1 L L t t B L dL i dU di Li L e e e e dt dt dt R R R ε ⎛⎞ = = ⎜⎟
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This note was uploaded on 06/03/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.

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