PiRReRRettLLthermal==−=−−−22222211εεττchch. We equate this to dUB/dt, and solve for the time: ()22211ln 237.0ms ln 225.6ms.LtLeeetRRτ−−=−⇒===61. From Eq. 30-49 and Eq. 30-41, the rate at which the energy is being stored in the inductor is 22/21LLttBLdLidUdiLiLeeeedtdtdtRRRε−−⎛⎞=−=−⎜⎟
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This note was uploaded on 06/03/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.