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63. (a) If the battery is applied at time
t
= 0 the current is given by
i
R
e
t
L
=−
−
ε
τ
1
ch
,
where
is the emf of the battery,
R
is the resistance, and
L
is the inductive time constant
(
L
/
R
). This leads to
e
iR
t
iR
t
L
L
−
=− ⇒− =
−
F
H
G
I
K
J
ετ
11
ln
.
Since
ln
ln
..
.
.,
200 10
100 10
50 0
05108
33
−
F
H
G
I
K
J
××
L
N
M
M
O
Q
P
P
−
iR
A
V
c
hc
h
Ω
the inductive time constant is
L
= t
/0.5108 = (5.00
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This note was uploaded on 06/03/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.
 Spring '08
 Any
 Physics, Current, Resistance

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