ch30-p095 - 95. (a) As the switch closes at t = 0, the...

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2 bat || 40 V 8.0 10 A s . 0.050 H L di dt L ε == = × (c) This circuit becomes equivalent to that analyzed in §30-9 when we replace the parallel set of 20000 resistors with R = 10000 . Now, with τ L = L / R = 5 × 10 –6 s, we have t / L = 3/5, and we apply Eq. 30-41: () 35 3 bat 11 . 8 1 0 A . ie R −− =− × (d) The rate of change of the current is figured from the loop rule (and Eq. 30-35): bat ||0 . L iR −= Using the values from part (c), we obtain | L | 22 V. Then, 2 bat 22 V 4.4 10 A s . 0.050 H L di dt L × (e) As t →∞ , the circuit reaches a steady state condition, so that di bat / dt = 0 and L = 0. The loop rule then leads to 3 bat bat 40 V 4 . 0 1 0A . 10000 L i εε −−=
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This note was uploaded on 06/03/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.

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