r==160054296....MHzMHzSince the additional capacitor is in parallel with the tuning capacitor, its capacitance adds to that of the tuning capacitor. If Cis in picofarads (pF), then CC++=36510pFpFThe solution for Cis C=−−=3652 961013622pFpFpF.bgbg bgbg..(c) We solve fLC=12/πfor L. For the minimum frequency C= 365 pF + 36 pF = 401 pF and f= 0.54 MHz. Thus LCf××=×−−1212401 10054 1022 1022212624ππchchFHzH... 15. (a) Since the frequency of oscillation
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