20. (a) From V = IXCwe find ω = I/CV. The period is then T= 2π/ω= 2πCV/I= 46.1 µs. (b) The maximum energy stored in the capacitor is 272911(2.20 10F)(0.250 V)6.88 10 J22EUCV−−==×=×. (c) The maximum energy stored in the inductor is also 2/2BULI==6.88 nJ . (d) We apply Eq. 30-35 as V= L(di/dt)max . We can substitute L = CV2/I2(combining what we found in part (a) with Eq. 31-4) into Eq. 30-35 (as written above) and solve for
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This note was uploaded on 06/03/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.