20. (a)
From
V = IX
C
we find
ω
=
I/CV
.
The period is then
T
= 2
π
/
ω
= 2
π
CV/I
= 46.1
µ
s.
(b) The maximum energy stored in the capacitor is
27
2
9
11
(2.20 10
F)(0.250 V)
6.88 10 J
22
E
UC
V
−−
==
×
=
×
.
(c) The maximum energy stored in the inductor is also
2
/2
B
UL
I
=
=
6.88 nJ .
(d) We apply Eq. 3035 as
V
=
L
(
di/dt
)
max
. We can substitute
L = CV
2
/I
2
(combining
what we found in part (a) with Eq. 314) into Eq. 3035 (as written above) and solve for
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This note was uploaded on 06/03/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.
 Spring '08
 Any
 Physics, Energy

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