ch31-p020 - 20(a From V = IXC we find = I/CV The period is...

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20. (a) From V = IX C we find ω = I/CV . The period is then T = 2 π / ω = 2 π CV/I = 46.1 µ s. (b) The maximum energy stored in the capacitor is 27 2 9 11 (2.20 10 F)(0.250 V) 6.88 10 J 22 E UC V −− == × = × . (c) The maximum energy stored in the inductor is also 2 /2 B UL I = = 6.88 nJ . (d) We apply Eq. 30-35 as V = L ( di/dt ) max . We can substitute L = CV 2 /I 2 (combining what we found in part (a) with Eq. 31-4) into Eq. 30-35 (as written above) and solve for
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This note was uploaded on 06/03/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.

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