ch31-p022 - 1 1 22. (a) We use U = 2 LI 2 = 2 Q 2 / C to...

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(c) Referring to Fig. 31-1, we see that the required time is one-fourth of a period (where the period is the reciprocal of the frequency). Consequently, tT f === × 1 4 1 4 1 4 133 10 188 10 3 4 . . Hz s. e j 22. (a) We use UL I Q C == 1 2 2 1 2 2 / to solve for L : () 2 22 2 63 max max 3 1 1 1.50V 4.00 10 F 3.60 10 H. 50.0 10 A CV V Q LC CI C I
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This note was uploaded on 06/03/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.

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