24. The assumption stated at the end of the problem is equivalent to setting
φ
= 0 in Eq.
3125. Since the maximum energy in the capacitor (each cycle) is given by
qC
max
/
2
2,
where
q
max
is the maximum charge (during a given cycle), then we seek the time for
which
2
2
max
max
1
.
22
2
2
q
QQ
q
CC
=⇒
=
Now
q
max
(referred to as the
exponentially decaying amplitude
in §315) is related to
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This note was uploaded on 06/03/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.
 Spring '08
 Any
 Physics, Charge, Energy

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