24. The assumption stated at the end of the problem is equivalent to setting φ= 0 in Eq. 31-25. Since the maximum energy in the capacitor (each cycle) is given byqCmax/22,where qmaxis the maximum charge (during a given cycle), then we seek the time for which 22maxmax1.2222qQQqCC=⇒=Now qmax(referred to as the exponentially decaying amplitudein §31-5) is related to
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This note was uploaded on 06/03/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.