31. (a) The current amplitude Iis given by I = VL/XL, where XL= ωdL = 2πfdL. Since the circuit contains only the inductor and a sinusoidal generator, VL= εm. Therefore, 330.0V0.0955A95.5 mA.22Hz)(50.0 10 H)mLLdVIXfL3−=====ππ(1.00×10×(b) The frequency is now eight times larger than in part (a), so the inductive reactance
This is the end of the preview. Sign up
access the rest of the document.
This note was uploaded on 06/03/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.