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31. (a) The current amplitude
I
is given by
I = V
L
/
X
L
, where
X
L
=
ω
d
L = 2
π
f
d
L
. Since the
circuit contains only the inductor and a sinusoidal generator,
V
L
=
ε
m
. Therefore,
3
30.0V
0.0955A
95.5 mA.
2
2
Hz)(50.0 10 H)
m
L
Ld
V
I
Xf
L
3−
==
=
=
=
ππ
(
1
.
0
0
×
1
0
×
(b) The frequency is now eight times larger than in part (a), so the inductive reactance
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This note was uploaded on 06/03/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.
 Spring '08
 Any
 Physics, Current

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