ch31-p035 - 35. (a) Now XL = 0, while R = 200 and XC =...

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35. (a) Now X L = 0, while R = 200 and X C = 1/2 π f d C = 177 Ω. Therefore, the impedance is 22 2 2 (200 ) (177 ) 267 . C ZR X =+ = +Ω = (b) The phase angle is 11 0 177 =tan tan 41.5 200 LC XX R φ −− ⎛⎞ −Ω = =− ° ⎜⎟ ⎝⎠ (c) The current amplitude is 36.0 V 0.135 A . 267 m I Z ε == = (d) We first find the voltage amplitudes across the
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This note was uploaded on 06/03/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.

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