Ch31-p039 - 39(a The capacitive reactance is XC = 1 1 1 = = = 37.9 d C 2f d C 2(60.0 z(70.0 106 F The inductive reactance 86.7 is unchanged The new

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6 11 1 37.9 . 2 2 z)(70.0 10 F) C dd X Cf C ω = == = π π(60.0 Η × The inductive reactance 86.7 is unchanged. The new impedance is 22 2 2 ( ) (200 ) (37.9 86.7 ) 206 . LC ZRX X =+ = + −Ω = (b) The phase angle is 86.7 37.9 tan tan 13.7 . 200 XX R φ −− ⎛⎞ Ω− = ° ⎜⎟ ⎝⎠ (c) The current amplitude is 36.0 V 0.175A. 206 m I Z ε = (d) We first find the voltage amplitudes across the circuit elements:
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This note was uploaded on 06/03/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.

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