method 1
: At
ω
d
= 50 rad/s, we have
Z
≈
700
Ω
which gives
C
= (
ω
d
Z
2

R
2
)
−
1
= 41
µ
F.
method 2
: At
ω
d
= 50 rad/s, we have
X
C
≈
500
Ω
which gives
C
= (
ω
d
X
C
)
−
1
= 40
µ
F.
method 3
: At
ω
d
= 250 rad/s, we have
X
C
≈
100
Ω
which gives
C
= (
ω
d
X
C
)
−
1
= 40
µ
F.
40. (a) The circuit has a resistor and a capacitor (but no inductor).
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This note was uploaded on 06/03/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.
 Spring '08
 Any
 Physics, Resistance

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