ch31-p050 - 50. (a) The capacitive reactance is XC = 1 1 =...

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50. (a) The capacitive reactance is 6 11 16.6 . 2 2 H z ) ( 2 4 . 01 0F ) C X fC == = π π(400 × (b) The impedance is 22 2 2 23 2 () ( 2) (220 ) [2 Hz)(150 10 H) 16.6 ] 422 . LC C ZRX X R f L X =+ π = + π(400 × = (c) The current amplitude is I Z m = ε 220 0521 V 422 A. . (d) Now XC C eq 1 . Thus, X C increases as C eq decreases. (e) Now
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