ch31-p078 - 78. (a) We find L from X L = L = 2 fL: XL 130...

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78. (a) We find L from XLf L L = = ω 2 π : f X L L == × × 2 130 10 24 5 01 0 460 10 3 3 3 π π . . . H Hz. c h (b) The capacitance is found from X C = ( C ) –1 = (2 π fC ) –1 : C fX C ×× 1 2 1 2 4 60 10 130 10 266 10 33 8 π π .. . Hz F. c hc h (c) Noting that X L f and X C f –1 , we conclude that when
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