78. (a) We find Lfrom XLfLL==ω2π: fXLL==××=×−2130 10245010460 10333ππ...ΩHHz.ch(b) The capacitance is found from XC= (C)–1= (2πfC)–1: CfXC××−12124 60 10130 10266 10338ππ...HzF.chchΩ(c) Noting that XL∝fand XC∝f –1, we conclude that when
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