ch31-p091

# ch31-p091 - 91. When the switch is open, we have a series...

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91. When the switch is open, we have a series LRC circuit involving just the one capacitor near the upper right corner. Eq. 31-65 leads to o 1 tan ( 20) tan20. d d L C R ω φ = =− ° = ° Now, when the switch is in position 1, the equivalent capacitance in the circuit is 2 C . In this case, we have 1 1 2 tan tan10.0 . d d L C R = Finally, with the switch in position 2, the circuit is simply an LC circuit with current amplitude 2 2 1 1 mm m LC d d d d I Z L C L C ε εε == = ⎛⎞ ⎜⎟ ⎝⎠ where we use the fact that 1 () dd CL > in simplifying the square root (this fact is evident from the description of the first situation, when the switch was open). We solve
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## This note was uploaded on 06/03/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.

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