This preview shows page 1. Sign up to view the full content.
93. (a) We observe that
ω
= 6597 rad/s, and, consequently,
X
L
= 594
Ω
and
X
C
= 303
Ω
.
Since
X
L
> X
C
, the phase angle is positive:
60.0
φ
=
+°
.
From Eq. 3165, we obtain
R
XX
LC
=
−
=
tan
.
168
Ω
(b) Since we are already on the “high side” of resonance, increasing
f
will only decrease
the current further, but
decreasing f
brings us closer to resonance and, consequently, large
values of
I
.
(c) Increasing
This is the end of the preview. Sign up
to
access the rest of the document.
This note was uploaded on 06/03/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.
 Spring '08
 Any
 Physics

Click to edit the document details