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() 22 2 00 max max max max max 2 m a x cos 22 2 for 2 RRR dE dV BV t rd t r d d t r d RV rR rd µε ωω ω ⎛⎞ ⎛ ⎞ === ⎜⎟ ⎜ ⎟ ⎝⎠ ⎝ ⎠ =≥ (note the B ∝ r –1 dependence — See also Eqs. 32-16 and 32-17). The plot (with SI units understood) is shown below. 7. (a) Noting that the magnitude of the electric field (assumed uniform) is given by E = V / d (where d = 5.0 mm), we use the result of part (a) in Sample Problem 32-1 . rr dE dV B dt d dt µ εµ ε == ≤ We also use the fact that the time derivative of sin ( t ) (where = 2 π f = 2 π (60) ≈ 377/s in this problem) is cos( t ). Thus, we find the magnetic field as a function of r (for r ≤ R ; note that this neglects “fringing” and related effects at the edges): 00 m a x max max cos V tB dd εµε
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This note was uploaded on 06/03/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.
- Spring '08