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()
22 2
00
max
max
max
max
max
2
m
a
x
cos
22
2
for
2
RRR
dE
dV
BV
t
rd
t
r
d
d
t
r
d
RV
rR
rd
µε
ωω
ω
⎛⎞
⎛
⎞
===
⎜⎟
⎜
⎟
⎝⎠
⎝
⎠
=≥
(note the
B
∝
r
–1
dependence — See also Eqs. 3216 and 3217). The plot (with SI units
understood) is shown below.
7. (a) Noting that the magnitude of the electric field (assumed uniform) is given by
E =
V
/
d
(where
d
= 5.0 mm), we use the result of part (a) in Sample Problem 321
.
rr
dE
dV
B
dt
d
dt
µ
εµ
ε
==
≤
We also use the fact that the time derivative of sin (
t
) (where
= 2
π
f
= 2
π
(60)
≈
377/s
in this problem) is
cos(
t
). Thus, we find the magnetic field as a function of
r
(for
r
≤
R
; note that this neglects “fringing” and related effects at the edges):
00 m
a
x
max
max
cos
V
tB
dd
εµε
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This note was uploaded on 06/03/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.
 Spring '08
 Any
 Physics

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