ch32-p012 - 12. (a) Here, the enclosed electric flux is...

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12. (a) Here, the enclosed electric flux is found by integrating 3 2 00 1 2 (0.500 V/m s)(2 ) 1 23 rr E E rdr t rdr t r R R ππ π ⎛⎞ Φ= = = ⎜⎟ ⎝⎠ ∫∫ with SI units understood. Then (after taking the derivative with respect to time) Eq. 32-3 leads to 3 2 1 (2 ) r Br r R πε µ =− . For r = 0.0200 m and R = 0.0300 m, this gives B = 3.09 × 10 20 T. (b) The integral shown above will no longer (since now r > R ) have r as the upper limit;
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