(c) We now look for a solution in the exterior region, where the field is inversely proportional to r(by Eq. 32-17): BBRrmax.==300mT12.0mTwhich yields r= 4R= 4(1.20 cm) = 4.80 cm. 20. (a) Since i = id(Eq. 32-15) then the portion of displacement current enclosed is ()2,enc2/31.33A.9
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This note was uploaded on 06/03/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.