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(c) We now look for a solution in the exterior region, where the field is inversely
proportional to
r
(by Eq. 3217):
B
B
R
r
max
.
==
300mT
12.0mT
which yields
r
= 4
R
= 4(1.20 cm) = 4.80 cm.
20. (a) Since
i = i
d
(Eq. 3215) then the portion of displacement current enclosed is
()
2
,enc
2
/3
1.33A.
9
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This note was uploaded on 06/03/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.
 Spring '08
 Any
 Physics, Current

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