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i
=
12.0 V
20.0
x
10
6
Ω
e
−
t/
τ
= 3.50
×
10
−
7
A .
Since
i = i
d
(see Eq. 3215) and
r
= 0.0300 m, then (with plate radius
R
= 0.0500 m) we
find
77
13
0
22
(4
10 T m/A)(3.50 10
A)(0.030 m)
8.40 10
T
2
2 (0.050 m)
d
ir
B
R
µ
ππ
−−
−
π×
⋅
×
==
=
×
.
22. From Eq. 2811, we have
i
= (
ε
/
R
)
e
t/
τ
since we are ignoring the selfinductance of
the capacitor. Eq. 3216 gives
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 Spring '08
 Any
 Physics, Capacitance, Inductance

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