23. (a) Using Eq. 27-10, we find EJiA===×⋅×=−−ρ162 10100500 100 32486....ΩmAmVm2chbg(b) The displacement current is ()()1280000168.85 10F/m 1.62 102000A s2.87 10A.EdddEdidiiAAdtdtdtAdtεεεε−−−Φ⎛⎞==××Ω⎜⎟
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This note was uploaded on 06/03/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.