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Unformatted text preview: 2 25. (a) Eq. 3216 (with Eq. 265) gives, with A = πR , µ0id r µ0 J d Ar µ0 J d (π R 2 )r 1
=
=
= µ0 J d r
B=
2π R 2
2π R 2
2π R 2
2
1
(4π× 10−7 T ⋅ m/A)(6.00 A/m 2 )(0.0200 m) = 75.4 nT .
2
µi
µ J π R2
= 67.9 nT .
(b) Similarly, Eq. 3217 gives B = 0 d = 0 d
2π r
2π r
= ...
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This note was uploaded on 06/03/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.
 Spring '08
 Any
 Physics

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