Ch32-p055 - 55(a The Pythagorean theorem leads to 2 B = Bh Bv2 = 0 3 cos m 0 3 sin m = 0 3 cos 2 m 4sin 2 m 4r 4r 2r 2 = 0 4r 3 2 1 3sin 2 m where

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55. (a) The Pythagorean theorem leads to 22 00 0 33 3 2 0 3 cos sin cos 4sin 42 4 13 s i n , 4 hv m m m m m BB B rr r r µµ ⎛⎞ =+ = λ + λ = λ + λ ⎜⎟ ππ π ⎝⎠ λ π where cos 2 λ m + sin 2 λ m = 1 was used. (b) We use Eq. 3-6: ( )
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This note was uploaded on 06/03/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.

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