Ch32-p056 - 56(a At the magnetic equator(m = 0 the field is B= 0 4r 3 410 = 7 T m A 8.00 1022 A m 2 4 6.37 10 m 6 3 = 3.10 105 T(b i = tan1(2 tan m

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56. (a) At the magnetic equator ( λ m = 0), the field is () ( ) 72 2 2 5 0 3 3 6 4 10 T m A 8.00 10 A m 3.10 10 T. 4 46 . 3 71 0m B r µµ π× × == = × π (b) φ i = tan –1 (2 tan λ m ) = tan –1 (0) = 0 ° . (c) At λ m = 60.0°, we find 25 2 5 0 3 1 3sin 3.10 10 1 3sin 60.0 5.59 10 T. 4 m B r −− =+ λ = ×+ ° = × π (d) i = tan –1 (2 tan 60.0°) = 73.9°.
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This note was uploaded on 06/03/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.

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