ch32-p062 - 62. (a) Eq. 30-22 gives B = 0ir = 222 T . 2 R 2...

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62. (a) Eq. 30-22 gives 0 2 222 T 2 ir B R µ π == . (b) Eq. 30-19 (or Eq. 30-6) gives 0 167 T 2 i B r . (c) As in part (b), we obtain a field of 0 22.7 T 2 i B r . (d) Eq. 32-16 (with Eq. 32-15) gives 0 2 1.25 T 2 d ir B R . (e) As in part (d), we get 0 2 3.75 T 2 d B R . (f) Eq. 32-17 yields B = 22.7 µ T. (g) Because the displacement current in the gap is spread over a larger cross-sectional
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This note was uploaded on 06/03/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.

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