λπ2LCc=.The solution for Lis LCc==×××=×−−−λππ2229221282214550 10417 102 998 10500 10mFm/sH.chchch.. This is exceedingly small. 5. If fis the frequency and λis the wavelength of an electromagnetic wave, then fλ= c. The frequency is the same as the frequency of oscillation of the current in the
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This note was uploaded on 06/03/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.