This preview shows page 1. Sign up to view the full content.
16. (a) The expression
E
y
= E
m
sin(
kx
–
ω
t
) it fits the requirement “at point
P
… [it] is
decreasing with time” if we imagine
P
is just to the right (
x
> 0) of the coordinate origin
(but at a value of
x
less
than
π
/2
k
=
λ
/4 which is where there would be a maximum, at
t
=
0).
It is important to bear in mind, in this description, that the wave is moving to the right.
Specifically,
1
(1/ ) sin (1/ 4)
P
xk
−
=
so that
E
y
=
(1/4)
E
m
at
t
= 0, there.
Also,
E
y
=
0
with our choice of expression for
E
y
.
Therefore, part (a) is answered simply by solving
This is the end of the preview. Sign up
to
access the rest of the document.
This note was uploaded on 06/03/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.
 Spring '08
 Any
 Physics

Click to edit the document details