(c) At a distance rfrom the transmitter, the intensity is 2/2,IPr=πwhere Pis the power of the transmitter over the hemisphere having a surface area 22rπ. Thus ()( )2262322m1010W/m6.310W.I3−=π =π10×10×= ×17. (a) The average rate of energy flow per unit area, or intensity, is related to the electric field amplitude Emby
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