uIcfIc==+(),10the same as radiation pressure. 23. Let fbe the fraction of the incident beam intensity that is reflected. The fraction absorbed is 1 – f. The reflected portion exerts a radiation pressure of 02rf Ipc=and the absorbed portion exerts a radiation pressure of pca=−,10where I0is the incident intensity. The factor 2 enters the first expression because the momentum of the reflected portion is reversed. The total radiation pressure is the sum of the two contributions: 000total2(1)(1).rafIfIfIpppcc+−+=+==To relate the intensity and energy density, we consider a tube with length Aand cross-sectional area A, lying with its axis along the propagation direction of an electromagnetic
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This note was uploaded on 06/03/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.