24. (a) We note that the cross section area of the beam is πd 2/4, where dis the diameter of the spot (d= 2.00λ). The beam intensity is IPd==××=×−−ππ2392924500 102 00 633 104397 10/../..WmW/mbgch(b) The radiation pressure is pIcr××=2 998 101328...m/sPa. (c) In computing the corresponding force, we can use the power and intensity to eliminate the area (mentioned in part (a)). We obtain
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