ch33-p024 - 24(a We note that the cross section area of the...

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24. (a) We note that the cross section area of the beam is π d 2 /4, where d is the diameter of the spot ( d = 2.00 λ ). The beam intensity is I P d == × × π π 2 3 9 2 92 4 500 10 2 00 633 10 4 397 10 / . ./ .. W m W/m b gc h (b) The radiation pressure is p I c r × × = 2 998 10 132 8 . . . m/s Pa. (c) In computing the corresponding force, we can use the power and intensity to eliminate the area (mentioned in part (a)). We obtain
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This note was uploaded on 06/03/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.

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