24. (a) We note that the cross section area of the beam is πd 2/4, where dis the diameter of the spot (d= 2.00λ). The beam intensity is IPd==××=×−−ππ2392924500 102 00 633 104397 10/../..WmW/mbgch(b) The radiation pressure is pIcr××=2 998 101328...m/sPa. (c) In computing the corresponding force, we can use the power and intensity to eliminate the area (mentioned in part (a)). We obtain
This is the end of the preview. Sign up
access the rest of the document.
This note was uploaded on 06/03/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.