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28. The mass of the cylinder is
(
/ 4) ,
mD
H
ρπ
2
=
where
D
is the diameter of the cylinder.
Since it is in equilibrium
22
net
2
0.
44
r
HD g
D
I
Fm
g
F
c
⎛⎞
π
=−
=
−
=
⎜⎟
⎝⎠
We solve for
H
:
2
8
3
3
7
1
/4
2(4.60W)
m) / 4](9.8m/s )(3.0 10 m/s)(1.20 10 kg/m )
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 Spring '08
 Any
 Physics, Mass

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