28. The mass of the cylinder is (/ 4) ,mDHρπ2=where Dis the diameter of the cylinder. Since it is in equilibrium 22net20.44rHD gDIFmgFc⎛⎞π=−=−=⎜⎟⎝⎠We solve for H: 283371/42(4.60W)m) / 4](9.8m/s )(3.0 10 m/s)(1.20 10 kg/m )
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