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36. We examine the point where the graph reaches zero:
θ
2
= 160º.
Since the polarizers
must be “crossed” for the intensity to vanish, then
1
= 160º – 90º
= 70º.
Now we
consider the case
2
= 90º (which is hard to judge from the graph).
Since
θ
1
is still equal
to 70º, then the angle between the polarizers is now
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This note was uploaded on 06/03/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.
 Spring '08
 Any
 Physics

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