ch33-p042 - 42. We apply Eq. 33-40 (once) and Eq. 33-42...

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42. We apply Eq. 33-40 (once) and Eq. 33-42 (twice) to obtain 22 02 2 1 cos cos (90 ) 2 II θ . Using trig identities, we rewrite this as 2 2 0 1 sin (2 ) 8 I I = . (a) Therefore we find 2 = 1 2 sin –1 0.40 = 19.6 ° . (b) Since the first expression we wrote is symmetric under the exchange:
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