42. We apply Eq. 33-40 (once) and Eq. 33-42 (twice) to obtain 220221coscos (90)2IIθ=°−. Using trig identities, we rewrite this as 2201sin (2 )8II=. (a) Therefore we find 2= 12sin–10.40 = 19.6°. (b) Since the first expression we wrote is symmetric under the exchange:
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This note was uploaded on 06/03/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.