42. We apply Eq. 33-40 (once) and Eq. 33-42 (twice) to obtain 220221coscos (90)2IIθ=°−. Using trig identities, we rewrite this as 2201sin (2 )8II=. (a) Therefore we find 2= 12sin–10.40 = 19.6°. (b) Since the first expression we wrote is symmetric under the exchange:
This is the end of the preview. Sign up
access the rest of the document.