42. We apply Eq. 3340 (once) and Eq. 3342 (twice) to obtain
22
02
2
1
cos
cos (90
)
2
II
θ
=°
−
.
Using trig identities, we rewrite this as
2
2
0
1
sin (2 )
8
I
I
=
.
(a) Therefore we find
2
=
1
2
sin
–1
0.40 = 19.6
°
.
(b) Since the first expression we wrote is symmetric under the exchange:
This is the end of the preview. Sign up
to
access the rest of the document.
This note was uploaded on 06/03/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.
 Spring '08
 Any
 Physics

Click to edit the document details