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42. We apply Eq. 3340 (once) and Eq. 3342 (twice) to obtain
22
02
2
1
cos
cos (90
)
2
II
θ
=°
−
.
Using trig identities, we rewrite this as
2
2
0
1
sin (2 )
8
I
I
=
.
(a) Therefore we find
2
=
1
2
sin
–1
0.40 = 19.6
°
.
(b) Since the first expression we wrote is symmetric under the exchange:
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 Spring '08
 Any
 Physics

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