direction of the previous sheet. The transmitted radiation is polarized, with its direction of
polarization making an angle of 90° with the direction of polarization of the incident
radiation. The intensity is
2
0
cos (90 / )
n
I
In
=°
.
We want the smallest integer value of
n
for which this is greater than 0.60
I
0
. We start
with
n
= 2 and calculate
2
cos (90 / )
n
n
°
. If the result is greater than 0.60, we have obtained
the solution. If it is less, increase
n
by 1 and try again. We repeat this process, increasing
n
by 1 each time, until we have a value for which
2
cos (90 / )
n
n
°
is greater than 0.60. The
first one will be
n
= 5.
43. (a) The rotation cannot be done with a single sheet. If a sheet is placed with its
polarizing direction at an angle of 90° to the direction of polarization of the incident
radiation, no radiation is transmitted. It can be done with two sheets. We place the first
This is the end of the preview. Sign up
to
access the rest of the document.
This note was uploaded on 06/03/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.
 Spring '08
 Any
 Physics, Polarization, Radiation

Click to edit the document details