direction of the previous sheet. The transmitted radiation is polarized, with its direction of polarization making an angle of 90° with the direction of polarization of the incident radiation. The intensity is 20cos (90 / )nIIn=°. We want the smallest integer value of nfor which this is greater than 0.60I0. We start with n= 2 and calculate 2cos (90 / )nn°. If the result is greater than 0.60, we have obtained the solution. If it is less, increase nby 1 and try again. We repeat this process, increasing nby 1 each time, until we have a value for which 2cos (90 / )nn°is greater than 0.60. The first one will be n= 5. 43. (a) The rotation cannot be done with a single sheet. If a sheet is placed with its polarizing direction at an angle of 90° to the direction of polarization of the incident radiation, no radiation is transmitted. It can be done with two sheets. We place the first
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This note was uploaded on 06/03/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.